## 1 two boxes m1 70 0 kg and m2 49 0 kg are co

### -6 Newton's Second Law - North Allegheny

There are two forces on the 2.00 kg box in the overhead view of Fig. 5-31, but only one is shown. For F 1 = 20.0 N, a = 12.0 m/s 2, and = 30.0°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) an angle relative to the positive direction of the x axis. Figure 5-31 Problem 7. Answer:

### 6.2 Friction University Physics Volume 1

At a post office, a parcel that is a 20.0-kg box slides down a ramp inclined at $30.0\text{°}$ with the horizontal. The coefficient of kinetic friction between the box and plane is 0.0300. (a) Find the acceleration of the box. (b) Find the velocity of the box as it reaches the end of the plane, if the length of the plane is 2 m A block(1) of mass, m1= 3.2 kg, moving at speed 0.85 m/s Oct 24, 2015 · A block(1) of mass, m1= 3.2 kg, moving at speed 0.85 m/s hits another block (2) m2=2.7 kg at rest. After collision, both blocks stick and slide together on frictionless surface at the same speed. how to find the ratio of Kinetic energy (final/initial) ?

### Collisions - Boston University

== =2 4.0 m /s 2.0 m/s. 22. vgh == =2 1.0 m /s 1.0 m/s. 22 (h = 0.2 m) (h = 0.05 m) 12. Two pendulums:Find the mass of ball B. Apply momentum conservation. How do we account for the fact that momentum is a vector? mv mv mv mv. A Ai B Bi A Af B Bf + =+ mv mv mv. A Ai A Af B Bf +0 =+ ×+ × == + (4 kg) ( 4 m/s) (4 kg) ( 2 m/s) 1 m/s Inclined plane and pulley:how to know the acceleration's Feb 13, 2015 · Homework Statement A block of mass m1= 3.70 kg on a frictionless plane inclined at angle =30.0° is connected by a cord over a massless, frictionless pulley to a second block of mass m2=2.30 kg. What are (a) the magnitude of the acceleration of each

### PHYSICS MIDTERM PRACTICE QUESTIONS Flashcards Quizlet

Two forces, F1 and F2, act on the 7.00-kg block shown in the drawing. The magnitudes of the forces are F1 = 45.0 N and F2 = 25.0 N. F1 is 70 degrees north of west and pushing the box toward the east. Physic 231 Lecture 9 - Michigan State University Two packing crates of masses 10.0 kg and 5.00 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 5.00-kg crate lies on a smooth incline of angle 40.0°. Find the acceleration of the 5.00-kg crate and the tension in the string. ()()() ()

### Physics 140 HOMEWORK Chapter 5B

C(g a) = (10 kg)(9.8 m/s2 6.125 m/s2) = 36.7N. (Note that while you are holding the system, T2 = 98 N.) (b) x = v0t+(1/2)at2 = 0+(1/2)(6.125(0.250)2 = 0.191m. P57. A block of mass m1 = 3.70 kg on a frictionless plane inclined at angle = 30.0 is connected by a Physics 2111 Unit 6 - CODThe co-efficient of kinetic friction, m k, Because in case 2 the boxes are accelerating in case 2, M2 does not move, thus the string will be taught and will 1 = 19.0 kg and the mass of the larger block is m 2 = 85.0 kg. What minimum force F is needed to keep M 1 from

### Pingry School

A 0.50 kg cart moves on a straight horizontal track. The graph of velocity versus time t for the cart is given below. v x (m/s) 1.0 0.8 0.6 -0.2 -0.4 - -0.8 -1.0 (a) Indicate every time t for which the cart is at rest. (b) Indicate every time interval for which the speed (magnitude of velocigy) of the cart is increasing. Problem 1 The system shown below has frictionless 1 = 3.8 kg and the shelf is 0.35. (a) Find the energy dissipated by friction when the block of mass m 2 = 2.2 kg falls a distance. (b) Find the change in the mechanical energy E mech of the two-block-Earth system during the time it takes the block of mass m 2 falls a distance y. (c) If they started from rest, use your result for Part (b) to

### Problem set 4.8 - TuHS Physics Home Page 1.1

The total weight would be:(1200 kg) (9.80 N/kg) = 11760 N down (-) the tension in the cable upward (T) with an upward (+) acceleration of .60 m/s/s. F = ma looks like:36. The two masses shown in figure 4-45 are each initially 1.80 m above the ground, and the massless Recitation Week 4 - Drexel Universityv2 0 2 sg = (22:4 m/s)2 2 0:600 9:80 m/s2 =42:5 m ; (29) which is much shorter. Problem 5.47. Two blocks connected by a rope of negligable mass are being dragged by a horizontal force (Fig. P5.47). Suppose F= 68:0 N, m 1 = 12:0 kg, m 2 = 18:0 kg, and the coe cient of kinetic friction between each block and the surface

### SOLUTION

k = 0.2. Solution Work. Consider the force equilibrium along the y axis by referring to the FBD of the crate, Fig. a, +cF y = 0; N + 500 sin 45° - 10(9.8 ) - 400 sin 30° = 0 N = 827.45 N Thus, the friction is F f = m kN = 0.2(827.45) = 165.49 N. Here, F 1 and F 2 do positive work whereas F f does negative work. W and N do no work U F 1 SOLUTIONS TO PROBLEM SET 8 Friedman1 2 mv2 + 0 = 0 + 1 2 k xcompressed 2 v = xcompressed k m = (0.220) 400 2.00 = 3.11 m s (b) How far does the block travel up the incline before starting to slide back down? At the top of its trajectory, the block will be momentarily at rest. In part (a) we implicitly chose the zero of gravita­

### Three blocks on a frictionless surface are connected by

Two blocks of mass m1 = 1.2 kg and m2 = 1.7 kg are connected by a massless string, as shown in the Figure. They are released from rest. The coefficent of kinetic friction between the upper block and the surface is 0.45. Calculate the speed of the blocks . please help me!! physics. The masses of blocks A and B are 4.5 kg and 3.7 kg respectively. manhassetschoolsboxes remain at rest, with the one on the right hanging vertically and the one on the left 2.0 meters from the bottom of an inclined plane that makes an angle of 600 with the horizontal. The coefficients of kinetic friction and static friction between the left-hand box and the plane are 0.15 and 0.30 respectively. You may use g = 10 m/s2. a.

### SOLVED:Two boxes, m_{1}=1.0 \mathrm{kg} with a co

Two boxes, m_{1}=1.0 \mathrm{kg} with a coefficient of kinetic friction of 0.10, and m_{2}=2.0 \mathrm{kg} with a coefficient of 0.20 , are placed on a plane i Hurry, space in our FREE summer bootcamps is running out. Claim your spot here.

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